# A Simple Nim（sg打表找规律）

Two players take turns picking candies from n heaps,the player who picks the last one will win the game.On each turn they can pick any number of candies which come from the same heap(picking no candy is not allowed).To make the game more interesting,players can separate one heap into three smaller heaps(no empty heaps)instead of the picking operation.Please find out which player will win the game if each of them never make mistakes.

Input
Intput contains multiple test cases. The first line is an integer

Output
For each test case,output a line whick contains either"First player wins."or"Second player wins".

Sample Input
2 2 4 4 3 1 2 4

Sample Output
Second player wins. First player wins.

Author
UESTC

Source

Recommend
wange2014   |   We have carefully selected several similar problems for you:   6742  6741  6740  6739  6738

#include<iostream>
#include<stdio.h>
#include<algorithm>
#include<string.h>
#include<vector>
using namespace std;
typedef long long ll;

//void getsg(int x){
//    memset(vis,0,sizeof(vis));
//    for(int i=0;i<x;i++){
//        vis[sg[i]]=1;
//    }
//    for(int i1=1;i1<x;i1++){
//        for(int i2=1;i2<x;i2++){
//            for(int i3=1;i3<x;i3++){
//                if(i1+i2+i3==x) vis[sg[i1]^sg[i2]^sg[i3]]=1;
//            }
//        }
//    }
//    for(int i=0;;i++){
//        if(vis[i]==0){
//            sg[x]=i;
//            break;
//        }
//    }
//}

int main(){
//    for(int i=1;i<=50;i++){
//        getsg(i);
//        printf("i:%d %d   %d\n",i,sg[i],sg[i]==i);
//    }
int t;
scanf("%d",&t);
while(t--){
int n;
scanf("%d",&n);
int ans=0;
int tem;
for(int i=1;i<=n;i++){
scanf("%d",&tem);
if(tem%8==0) tem--;
else if(tem%8==7) tem++;
ans=ans^tem;
}
if(ans==0) printf("Second player wins.\n");
else printf("First player wins.\n");
}
}

每一个你不满意的现在，都有一个你没有努力的曾经。
一个历史类的公众号，欢迎关注 