编译Lua而不在字符串和数字之间自动转换

Lua通常是一种 strongly-typed语言,几乎不提供数据类型之间的隐式转换.

但是,数字和字符串确实得到automatically coerced in a few cases

Lua provides automatic conversion between string and number values at run time. Any arithmetic operation applied to a string tries to convert this string to a number, following the rules of the Lua lexer. (The string may have leading and trailing spaces and a sign.) Conversely, whenever a number is used where a string is expected, the number is converted to a string, in a reasonable format

从而:

local x,y,z = "3","8","11"
print(x+y,z)  --> 11   11
print(x+y==z) --> false
print(x>z)    --> true

我不想要这个.如何重新编译Lua解释器以删除所有自动转换?

我更愿意:

print(x+y)    --> error: attempt to perform arithmetic on a string value
print(x>1)    --> error: attempt to compare number with string
print(x..1)   --> error: attempt to concatenate a number value
杰出的 LHF在上面评论说这不是开箱即用的,需要编辑Lua的内部,从 http://www.lua.org/source/5.2/lvm.c.html#luaV_tonumber开始

将此标记为答案以便结束此问题.如果有人后来选择提供有关需要做什么的深入细节的答案,我很乐意将接受标记切换到该答案.

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